Question

write the products and probable mechanism of the reaction: CH3Br+ aq.KOHof ​

Answer 1

CH3BR+KOH=CH3OH+KBR.........

Answer 2

The reaction will follow the nucleophilic substitution reaction.

Explanation:

Methyl bromide $(CH_{3}Br )$ is a primary haloalkane and it will undergo nucleophilic substitution by $SN^{2}$ mechanism. It takes place in a single step.

The aqueous KOH is a strong base, here the OH will act as a nucleophile and attack the methyl bromide.

When alkyl halides are treated with aqueous KOH, the halogen is substituted by OH, yielding alcohol.

Following the above point, the reaction will be

$CH_{3} Br + KOH_{aq.}$→$CH_{3}OH + KBr$

This reaction and mechanism are used in the production of alcohol.