Chemistry, asked by desha6026, 5 months ago

Write the products of the oxidation of propene by using cold aqueous solution of KMnO4 .​

Answers

Answered by laysanu204
1

Treatment of alkenes with cold, dilute basic KMnO4 leads to 1,2-diols (vicinal diols).

Answered by Anonymous
3

Answer:

This type of equation is quite commonly used in organic chemistry. Oxygen written in square brackets is taken to mean "oxygen from an oxidizing agent". The reason for this is that a more normal equation tends to obscure the organic change in a mass of other detail - as you will find below!

The full equation depends on the conditions.

Under acidic conditions, the manganate(VII) ions are reduced to manganese(II) ions.

Under alkaline conditions, the manganate(VII) ions are first reduced to green manganate(VI) ions . . .

. . . and then further to dark brown solid manganese(IV) oxide (manganese dioxide).

hope it helps you a little ☺️

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