CBSE BOARD XII, asked by harsur64031, 10 months ago

Write the program in javascript to solve the given polynomial =x^3+2x^2.y+3x.y^3=0

Answers

Answered by Shaizakincsem
5

The solution for the equation can be like this.

Explanation:

  • y^2 = x^3 + 2x - 3xy

  • (X^2+y^2-1)^3-x^2y^3=0

  • X^3+y^3=3xy^2-x-1

  • X^3+y^2=6xy/sqrt(y/x)

  • cos(PI*Y) = cos(PI.X)

  • The further explanation will be:

  • Y^2 + X^2 =1  ==>  Y= sqrt(1-X^2)

  • y1 = (-(-3x) - sqr((-3x)^2 - 4(-1)(x^3+2x)))/2*(-1)

  • y2 = (-(-3x) + sqr((-3x)^2 - 4(-1)(x^3+2x)))/2*(-1)
Answered by saachirawani
6

Answer:

The solution of an Equation can be like show in the pic

Attachments:
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