write the program to input the value of a,b and c of a quadratic equation ie ax²+bx+c=0,and display its root?
Answers
Answer:
Search Programiz
Get App
C Program to Find the Roots of a Quadratic Equation
In this example, you will learn to find the roots of a quadratic equation in C programming.
To understand this example, you should have the knowledge of the following C programming topics:
C Programming Operators
C if...else Statement
The standard form of a quadratic equation is:
ax2 + bx + c = 0, where
a, b and c are real numbers and
a != 0
The term b2-4ac is known as the discriminant of a quadratic equation. It tells the nature of the roots.
Answer:
#include <math.h>
#include <stdio.h>
int main() {
double a, b, c, discriminant, root1, root2, realPart, imagPart;
printf("Enter coefficients a, b and c: ");
scanf("%lf %lf %lf", &a, &b, &c);
discriminant = b * b - 4 * a * c;
// condition for real and different roots
if (discriminant > 0) {
root1 = (-b + sqrt(discriminant)) / (2 * a);
root2 = (-b - sqrt(discriminant)) / (2 * a);
printf("root1 = %.2lf and root2 = %.2lf", root1, root2);
}
// condition for real and equal roots
else if (discriminant == 0) {
root1 = root2 = -b / (2 * a);
printf("root1 = root2 = %.2lf;", root1);
}
// if roots are not real
else {
realPart = -b / (2 * a);
imagPart = sqrt(-discriminant) / (2 * a);
printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imagPart, realPart, imagPart);
}