write the proof as possible as early
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S10=n/2 (2a+(n-1)×d)
put a=6 and n=10
put 195 in place of S10
now by solving this we get d=3
now in LHS put the formula of Sn in the first ratio
in this formula put the value of d and a but don't put the value of n just keep it n
Similarly in the second ratio
try solving by this method
Hope it helps:)
put a=6 and n=10
put 195 in place of S10
now by solving this we get d=3
now in LHS put the formula of Sn in the first ratio
in this formula put the value of d and a but don't put the value of n just keep it n
Similarly in the second ratio
try solving by this method
Hope it helps:)
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