Write the proportionality of the corresponding sides of ∆CPA and ∆CQB
Answers
Answered by
6
Answer:
ΔCPA and ΔCQB
∠CPA≅∠CQB [each angle is measure 90
o
]
∠ACP≅∠BCQ [Common angle]
∴ΔCPA∼ΔCQB
[AA test]
∴
BC
AC
=
BQ
AP
[Corresponding sides of similar triangle]
∴
12
AC
=
8
7
∴AC=x=
8
12×7
∴AC=10.5units.
Step-by-step explanation:
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Answered by
0
Answer:
AC =10.5 cm
Step-by-step explanation:
given: AP=7,BQ=8,BC=12
TO PROVE:CPA~CQB
PROOF:
∠CPA=∠CQB
∠BCQ= ∠PAC (COMMON ANGLE)
Attachments:
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