write the pythagoras relation for the following right-angled triangles
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Step-by-step explanation:
The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides. In the given triangle ABC, we have BC2 = AB2 + AC2. Here, AB is the base, AC is the altitude or the height, and BC is the hypotenuse.
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Answer:
(i) PM^2=PN^2+MN^2
(ii) DE^2=DF^2+EF^2
Step-by-step explanation:
As in triangle PMN PM is the hypotenuse and in triangle DEF DF is the hypotenuse
the pythagorus theorem
hyp^2=adj^2+opp^2
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