write the pythagorean tripiet if one number is 14
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The formula is (2m)2,(m2 - 1)2,(m2 + 1)2
Smallest member = 2m = 14
2m = 14
m = 14/2 = 7
m2 - 1 = 72 - 1 = 49 - 1 = 48
m2 + 1 = 72 + 1 = 49 + 1 = 50
The required triplet is 14 , 48 and 50.
if you like my answer then please mark it as brainliest .........
Smallest member = 2m = 14
2m = 14
m = 14/2 = 7
m2 - 1 = 72 - 1 = 49 - 1 = 48
m2 + 1 = 72 + 1 = 49 + 1 = 50
The required triplet is 14 , 48 and 50.
if you like my answer then please mark it as brainliest .........
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