Write the Pythagorean triplet even number is 14
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Answered by
3
Heya friend,
Let 2m = 14
Then,
2m = 14
=> m = 14/2
=> m = 7
Therefore , m^2 + 1
= 7^2 + 1
= 49 + 1 = 50
m^2 - 1
= 7^2 - 1
= 49 - 1
= 48
Hence , the Pythagorean triplets are 14 , 48 , 50.
Thanks
With regards@
Tanisha
Let 2m = 14
Then,
2m = 14
=> m = 14/2
=> m = 7
Therefore , m^2 + 1
= 7^2 + 1
= 49 + 1 = 50
m^2 - 1
= 7^2 - 1
= 49 - 1
= 48
Hence , the Pythagorean triplets are 14 , 48 , 50.
Thanks
With regards@
Tanisha
Answered by
0
hello..
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15 ; m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15 ; m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
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