write the pythagorean triplet if one number is 14
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Answered by
56
Hi there,
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The formula is (2m)²,(m²-1)²,(m²+1)²
Smallest member = 2m = 14
2m = 14
m = 14/2 = 7
m²- 1 = 7²- 1 = 49 - 1 = 48
m²+ 1 = 7²+ 1 = 49 + 1 = 50
The required triplet is【14 , 48 and 50.】
_______________________________
HOPE THIS HELPS YOU:-))
_______________________________
The formula is (2m)²,(m²-1)²,(m²+1)²
Smallest member = 2m = 14
2m = 14
m = 14/2 = 7
m²- 1 = 7²- 1 = 49 - 1 = 48
m²+ 1 = 7²+ 1 = 49 + 1 = 50
The required triplet is【14 , 48 and 50.】
_______________________________
HOPE THIS HELPS YOU:-))
GOKUSS3:
greatly expained
Answered by
47
Pythagorean triplet formula are 2m , m²+1, m²-1
here m is Integer, m>1
2m= 14
m= 7
m²+1= 7²+1 = 49+1= 50
m²-1 = 7² -1 = 49 - 1=48
Pythagorean triplets are 14, 48, 50
here m is Integer, m>1
2m= 14
m= 7
m²+1= 7²+1 = 49+1= 50
m²-1 = 7² -1 = 49 - 1=48
Pythagorean triplets are 14, 48, 50
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