Question

write the Pythagorean triplet whose leat no is 18

Answer 1

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Here is your answer

PYTHAGOREAN TRIPLET
$2x \\ x {}^{2} - 1 \\ x {}^{2} + 1$
Always
2x is the smallest number

$2x = 18 \\ x = 9$
$x {}^{2} = 9 {}^{2} = 81$
$x {}^{2} - 1 = 81 - 1 = 80$
$x {}^{2} + 1 = 81 + 1 = 82$
Answers

18 , 80 , 82

Answer 2

The least no. is 18
So, 2m=18
m=18/2
9
2m =18

Now, m+1
=9+1=10
And, m-1
=9-1=8
Pythogorian triplet is 18,10,8