Question

write the pythagorean triplet whose members are formed by the given natural numbers: (1)6
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Answer 1

Answer:

2m, m²-1 and m²+1

So,

let's try m²-1=6

m²=7

m=✓7

The value of m won't be an integer

So,

Let's try for 2m = 6

m = 6/2

m = 3

Here the value of m will be an integer, so , m=3 is possible

Therefore,

2m = 6

m²-1=3²-1=8

m²+1=3²+1=10

Thus,

The Pythagorean triplet is 6,8 and 10