Question

WRITE THE PYTHAGOREAN TRIPLET WHOSE ONE MEMBER IS 18

Answer 1

If we take m2 + 1 = 18,
m2 = 17
The value of m will not be an integer.
If we take m2 − 1 = 18, then m2 = 19
Again the value of m is not an integer.
Let 2m =18
m = 9
Thus, m2 − 1 = 81 − 1 = 80 and m2 + 1 = 81 + 1 = 82
the Pythagorean triplet is 18, 80, and 82.
hope this will help you

Answer 2

here is ur answer

(2m)+(m^-1)=(m^2+1)

2m=18

2m=2×9

m=9

m^2-1=9^2-1

m^2-1=81-1

m^2-1=80

m^2+1=9^2+1

=81+1

m^2+1=82