Question

write the pythagorean triplet whose one number is 18​

Answer 1

Answer:

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Answer 2

Pythagorean Triplet is (H)²=(P²)+(B)²

Let the hypotenuse (H) = 18

and

Perpendicular (P) and Base(B) = x

Now, A/c to Pythagorean Triplet,

(H)²=(P²)+(B)²

(18)²=(x)²+(x)²

324=2x²

324/2=x²

162=x²

x=√162

x=12.7.