Write the Pythagorean triplet whose one of the number is 12?
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As we know (2n),(n^2+1)(n^2-1) is a pythagorean triplet where n is the number....
So 2n=12
=n=12/2=6
=(n^2+1)= 36+1=37
=(n^2-1)= 36-1=35
I hope it will help u..
In case of any doubt pls comment below.
And don't forget to mark as brainliest
So 2n=12
=n=12/2=6
=(n^2+1)= 36+1=37
=(n^2-1)= 36-1=35
I hope it will help u..
In case of any doubt pls comment below.
And don't forget to mark as brainliest
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