write the pythagorean triplet whose smallest
number is 9
Answers
Answered by
3
Answer:
Smallest number in a pythagoras theorom is 2m.
So, 2m = 9 => m = 4.5
Pythagorean Triplet = 2m, m^2 - 1, m^2 + 1
So, 9, 4.5^2 - 1, 4.5^2 + 1
= 9, 19.25, 21.25
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Answered by
0
Answer:9,19.25,21.25
Step-by-step explanation:
2M=9
M=4.5
m square - 1
4.5 square = 20.25
=20.25 - 1
=19.25
9,19.25,m square + 1
m square + 1
=20.25 + 1
=21.25
9,19.25,21.25
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