write the pythagorean triplets one of whose member is 10
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Phythagorean Triplet ( 6,8,10)
Pythagorean Triplet:
Three natural numbers m,n and p are said to form a Phythagorean Triplet (m,n,p), if m²+n²=p²
For every natural number m>1,
we have (2m, m²-1 , m²+1) as a Phythagorean Triplet.
Here,
m²+1 = 10
=> m² = 10 - 1
=> m² = 9
=> m = 3
Therefore,
2m = 2×3 = 6
m²-1 = 3² - 1 = 9 -1 = 8
m²+1 = 3² + 1 = 9 +1 = 10
Phythagorean Triplet ( 6,8,10)
6² + 8² = 10²
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