Question

write the pythogorean triplets whose one number is 63

Answer 1

Answer:

M^2-1=63

M^2-1=63m^2=63+1

M^2-1=63m^2=63+1m=under root 64=8

M^2-1=63m^2=63+1m=under root 64=82m =16

M^2-1=63m^2=63+1m=under root 64=82m =16m^2-1=63

M^2-1=63m^2=63+1m=under root 64=82m =16m^2-1=63m^2+1=65

M^2-1=63m^2=63+1m=under root 64=82m =16m^2-1=63m^2+1=65Mark as brainliest and thank and

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Answer 2

Answer:

6,7 may be the correct answer