write the quadratic equation 2y=8y-5 in syandarad form??
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(2y2 - 8y) - 5 = 0
Step-by-step explanation:
Factoring 2y2-8y-5
The first term is, 2y2 its coefficient is 2 .
The middle term is, -8y its coefficient is -8 .
The last term, "the constant", is -5
Step-1 : Multiply the coefficient of the first term by the constant 2 • -5 = -10
Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -8 .
-10 + 1 = -9
-5 + 2 = -3
-2 + 5 = 3
-1 + 10 = 9
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
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