Question

Write the quadratic equation for the following situtation, the difference of the ages of two friends
is 10 years. Four years latter, the product of their ages in the years is 48.​

Answer 1

Answer:

hi mate hope my answer finds you in the pink of your health--

Step-by-step explanation:

Let, the age of one friend be x and the age if other friend be y..

according to the question, x-y=10..--(1)

four years later, age of one friend =x+4.

age of the other friend =y+4..

according to the condition, (x+4)(y+4)=48

implies, xy+4x+4y+16=48.

implies, xy+4(x+y)=48-16=32.

implies, 4x+4y= 32-xy..----(2)

4x-4y= 40---(1)×4--(3)

--------------------

8x= 72-xy..

now from (1) x=10+y.

so 80+8y=72-(10+y)y

or, 80+8y= 72-10y-y^2.

hor, y^2+10y+8y+80-72.

or, y^2+18y+8=0.

is there any mistake in the question??

plzz check it again dear..