Question

write the quadratic equation if root 2 and 1/3 are the sum and product of its zeros respectively​

Answer 1

Step-by-step explanation:

Answer:

3x^2-3\sqrt{2}x+13x2−32x+1

Step-by-step explanation:

We have been given the two roots as \sqrt{2}2 and \frac{1}{3}31

We can find easily find the required quadratic equation with the given sum and product of the roots.

Any equation is in the form:-

x² - Sx + P = 0

Here,

S = Sum of Roots

P = Product of Roots

Substitute the values:-

x^{2}-(\sqrt{2})x+\dfrac{1}{3} =0x2−(2)x+31=0

Taking the LCM:-

\dfrac{3x^{2}-3\sqrt{2}x+1}{3}=033x2−32x+1=0

Multiply the equation with a constant 'K':-

K\left(\dfrac{3x^{2}-3\sqrt{2}x+1}{3}\right)=0K(33x2−32x+1)=0

Let K = 3

So, the equation becomes:-

3x^2-3\sqrt{2}x+1=03x2−32x+1=0

This is the required answer !