write the quadratic equation if the zeroes are alpha, beta and find the sum and product of zeroes of x^2-6x+9=0.
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5
Answer:
In the given polynomial x
2
−6x+9,
The first term is x
2
and its coefficient is 1.
The middle term is −6x and its coefficient is −6.
The last term is a constant term 9.
Multiply the coefficient of the first term by the constant 1×9=9.
We now find the factor of 9 whose sum equals the coefficient of the middle term, which is −6 and then factorize the polynomial x
2
−6x+9 as shown below:
x
2
−6x+9
=x
2
−3x−3x+9
=x(x−3)−3(x−3)
=(x−3)(x−3)
Therefore, x
2
−6x+9=(x−3)(x−3).
so the zero of the polynomial is 3.
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