Question

Write the quadratic equation in standard form given the sum and product of the roots: sum = ¾ and product = -1.

Answer 1

standard form of quadratic equations

kax^2 - bx + c =0

sum of roots= -b/a = 3/4

product of roots= c/a = -1

k{x^2 -(3/4)x +(-1)} = 0

let k = 4

then equation is

4x^2 -3x -4 =0

Answer 2

the quadratic equation in standard form is

kAx^2 - Bx + C =0  then the sum of the  roots given by $-b/a=3$

and the product of the roots are written as $c/a=-1$

∴$k<x^{2} -(3/4)x+(-1)>=0$

suppose k is 4 then the equation becomes $4x^{2} -3x-4=0$