Math, asked by smlab71019, 9 months ago

write the quadratic equation of whose roots are 1/root 2, 1/root2​

Answers

Answered by abhirajjha54
12

Answer:

x² -x/√2+1/2= 0 is ur ans

Answered by sharonr
0

The quadratic equation of whose roots are 1/root 2, 1/root 2​ are 2x^2 - 2\sqrt{2}x + 1 = 0

Solution:

The quadratic equation is given as:

x^2 - (\text{ sum of zeros })x + \text{ product of zeros } = 0

From given,

Zeros = \frac{1}{\sqrt{2}} , \frac{1}{\sqrt{2}}

Thus,

\text{sum of zeros } = \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}} \\\\

\text{sum of zeros } = \frac{2}{\sqrt{2}}

\text{product of zeros } = \frac{1}{\sqrt{2}} \times  \frac{1}{\sqrt{2}}\\\\\text{product of zeros } = \frac{1}{2}

Therefore,

x^2 - \frac{2}{\sqrt{2}}x + \frac{1}{2} = 0\\\\x^2 - \sqrt{2}x + \frac{1}{2} = 0\\\\2x^2 - 2\sqrt{2}x + 1 = 0

Thus the equation is found

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