write the quadratic equation q =75-21q2 in standard form find the value of this discriminant. write the nature of its roots
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Step-by-step explanation:
q =75-21q2
-21q²+q-75=0
by changing sign,
21q-q+75=0
compare equation with aq²+bq+c=0
a=21;b=-1;c=-75
b²-4ac=(-1)²-4×21×(-75)
=1+6300
= 6301
b²-4ac>0
therefore the roots of equation is real and equal.
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