Question

write the quadratic equation to find two consecutive numbers whose product is 156​

Answer 1

Let the two integers be xandx+1.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.x2+x−156=0.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.x2+x−156=0.They will need to be very close to √156 , so lets start there. √156=12.4899.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.x2+x−156=0.They will need to be very close to √156 , so lets start there. √156=12.4899.12×13=156 which gives us exactly what we want.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.x2+x−156=0.They will need to be very close to √156 , so lets start there. √156=12.4899.12×13=156 which gives us exactly what we want.(x+13)(x−12)=0.

Let the two integers be xandx+1.x×(x+1)=156 this leads to a quadratic equation.x2+x−156=0.They will need to be very close to √156 , so lets start there. √156=12.4899.12×13=156 which gives us exactly what we want.(x+13)(x−12)=0.x=−13orx=12 reject 12 as we are looking for negative integers.

Answer 2

Answer:

let one consecutive number = x

other consecutive number = x+1

product of the numbers = 156

x ( x+1) = 156

x^2+x - 156 = 0

I think this is the answer.........I hope it helps you