Question

Write the quadratic equation whose roots are 3 and 8

Answer 1

α=3   β=8

p(x)=k[x²-(α+β)x+αβ]

p(x)=k[x²-(3+8)x+(3*8)]

p(x)=k[x²-(11)x+(24)]

let k=1

p(x)=x²-11x+24

Answer 2

The quadratic equation whose roots are 3 and 8 is  $x^2-11x+24=0$

Step-by-step explanation:

To find : Write the quadratic equation whose roots are 3 and 8 ?

Solution :

The roots of the quadratic equation $ax^2+bx+c=0$ are $\alpha$  and $\beta$.

So, Let $\alpha=3$  and $\beta=8$

The formula to get the equation is

$x^2-(\alpha+\beta)x+\alpha\beta=0$

Substitute the values,

$x^2-(3+8)x+(3)(8)=0$

$x^2-11x+24=0$

Therefore, the quadratic equation whose roots are 3 and 8 is  $x^2-11x+24=0$

#Learn more

Write quadratic equation whose roots are  2 and 4.​

https://brainly.in/question/9909477