Question

write the quadratic formula for finding the roots of the equation X square BX C 0​

Answer 1

Step-by-step explanation:

ax² + bx +c

Let x be the root

$\boxed{\boxed{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }}$

Answer 2

$\boxed{ \sf{Quadratic \: Equation}}$

⟹ ax² + bx + c = 0

This is basically the standard form of Quadratic Equation.

And rhe value of x will be calculated in the following way :

$\boxed {\sf{ Quadratic \: Formula}}$

$x = \dfrac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, b² - 4ac is taken as the discriminant.

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$\sf{if \: \alpha \: and \: \beta \: are \: the \: zeroes \: of \: a {x}^{2} + bx + c = 0 \: then}$

$\alpha = \dfrac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}$ and $\beta = \dfrac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a}$

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