write the quadratic polynomial p(y) with -15 and-7 as sum and one of the zeroes resp.
Answers
Answered by
0
Answer:
Given the polynomial x
2
−3x−5
For solving we have to make it a zero,
∴x
2
−3x−5=0
Now, by formula,
x=
2⋅1
−(−3)±
(−3)
2
−4⋅1⋅(−5)
=
2
3±
9+20
=
2
3±
29
∴x=
2
3+
29
,
2
3−
29
∴ Sum of the roots, (S)=
2
3+
29
+
2
3−
29
=
2
3+
29
+3−
29
=
2
6
=3
and product of the roots, (P)=(
2
3+
29
)×(
2
3−
29
)
=
4
9−29
=
4
−20
=−5
Now, using S and P as zeros we have,
x=3
⇒x−3=0
and x=−5
⇒x+5=0
∴ the required polynomial is,
(x−3)(x+5)
=x
2
+2x−15.
Answered By 0mk@r
Step-by-step explanation:
please mark me as brainliest
Similar questions