write the quadratic polynomial p(y) with -15 and-7 as sum and one of the zeroes.
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Step-by-step explanation:
one zero =-7
sum of zeroes=-15
other zero=-15-(-7)=-8
product of zeroes=(-7)×(-8)=56
the quadratic polynomial is
k [x^2-(sum of zeroes)x+(product of zeroes)] where k is constant.
so.,
x^-(-15)x+56
the quadratic polynomial is
x^2+15x+56
I hope it helps
happy navratri
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