Question

Write the quadratic polynomial where zeroes are 2/3 and -1/3


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Answer 1

Step-by-step explanation:

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Let quadratic function be f(x)

ᴀʟᴘᴀ = 2/3 ʙᴇᴛᴀ = -1/3

f(x) = x²- (ᴀ + ß) x + (ᴀ × ß)

f(x) = x²- (2/3 - 1/3)x + (2/3×-1/3)

f(x) = x²- (1/3)x + (6 × -3)

f(x) = x²- 1/3x - 18

f(x) = 3x²- x - 18 Ans.

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