Question

Write the quadratic polynomial whose one zero is 6 and sum of zero's is 0​

Answer 1

Answer:

$\alpha = 6$

$\beta = 0$

and

$\alpha + \beta = 6 + 0 = 6$

$\alpha \times \beta = 6 \times 0 = 0$

therefore

${x}^{2} + ( \alpha + \beta )x + ( \alpha \beta )$

${x}^{2} + 6x + 0$

or

x²+6x is the quadratic equation

hope it help

Answer 2

Answer:

x^2 - 36

Step-by-step explanation:

Given: A zero is 6

Sum of zero is 0

To find: Quadratic Polynomial

Solution: Let take the zeroes be alpha(p) and beta(q)

A/q

p=6

alpha + beta = 0

6 + q = 0

q = 0 - 6

q = -6

Product of zeroes = alpha × beta

p × q = 6 × -6

pq = -36

Quadratic Equation

=> x^2 - ( p+q ) x + pq

=> x^2 - 0x + (-36)

=> x^2 - 36

Ans