Write the Quadratic polynomial whose zeros are -3 and 2?
Answers
Answered by
0
Answer:
α=2
\beta = -6β=−6
As we know ,
= > x^2- (\alpha+\beta)x + (\alpha.\beta)=>x2−(α+β)x+(α.β)
= > x^2- (2-6)x +(2×-6)=>x2−(2−6)x+(2×−6)
= > x^2 - (-4)x +(-12)=>x2−(−4)x+(−12)
= > x^2 + 4x -12=>x2+4x−12
Therefore,the required quadratic polynomial is x^2 +4x -12x2+4x−12
Answered by
0
Step-by-step explanation:
x=-3,2
(x+3)(x-2)=0
x²+x-6=0
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