Question

Write the quadratic polynomial whose zeros are write the quadratic polynomial whose zeros are √3 and -
√3

Answer 1

Answer:

$x^2-3$

Step-by-step explanation:

$(x-\sqrt{3} )(x+\sqrt{3})=0$

Brainliest please

Answer 2

Answer:

x^2-3=0

Step-by-step explanation:

The roots are

$\sqrt{3} \: and- \sqrt{3}$

Therefore the polynomial are:

$(x - \sqrt{3)} (x - ( - \sqrt{3)) } = 0 \\ (x - \sqrt{3)(} x + \sqrt{3)} = 0 \\ {x}^{2} - 3 = 0$