Question

write the quantient when the sum of a 2 digit number 23 and now obtained by reversing the digit is divided by
( a) =11
(b)= sum of the digits​

Answer 1

Part i). The Quotient is 5

Part ii). The Quotient is 11

Given :

The sum of a 2 digit number 23.

The number we obtained by reversing the digit is 32.

• Sum of the numbers :

→ 23 + 32

→ 55

• Sum of the digits 23 or 32 :

→ 3 + 2

→ 5

Now,

Part i),

Find the quotient when 55 is divided by 11.

So,

$\sf \implies \dfrac{55}{11} = 5$

_____________________________

Part ii),

Find the quotient when 55 is divided by 5.

So,

$\sf \implies \dfrac{55}{5} = 11$

Hence,

Part i). The Quotient is 5

Part ii). The Quotient is 11

Answer 2

Part i). The Quotient is 5

Part ii). The Quotient is 11

Given :

The sum of a 2 digit number 23.

The number we obtained by reversing the digit is 32.

• Sum of the numbers :

→ 23 + 32

→ 55

• Sum of the digits 23 or 32 :

→ 3 + 2

→ 5

Now,

Part i),

Find the quotient when 55 is divided by 11.

So,

$\frac{55}{11 } = 5$

_____________________________

Part ii),

Find the quotient when 55 is divided by 5.

So,

$\frac{55}{5} = 11$

Hence,

Part i). The Quotient is 5

Part ii). The Quotient is 11