Question

Write the quantum number of last electron of aluminium

Answer 1

Answer:

Electronic configuration of aluminum is 1s

2

2s

2

2p

6

3s

2

3p

1

hence, the outermost electron enters in M shell i.e n=3. The outermost electron enters into the p subshell i.e l=1. As the electron enters in p

x

orbital hence, m=−1. For first electron s=+

2

1

.

Set of quantum numbers (n,l,m,s) for outermost aluminium gaseous atom is (3,1,−1,+

2

1

).

Answer 2

Answer:

For Al, the principal quantum number for the valence shell electron is 3. The angular momentum number (l) has a value of 0 to n-1. For n = 3, the angular momentum quantum number is 0, 1 or 2. These numbers correspond to the subshells, s, p, d, f, etc.