write the quatratic quation 7-4x-x2 in the standard form
Answers
Answer:
-x2-4x+7
Step-by-step explanation:
multiply whole eqn by - sign
x2+4x-7 is the standard form
Concept:
The definition of a quadratic equation as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. The quadratic equation has the following generic form:
ax² + bx + c = 0
where a, b, and c are numerical coefficients and x is an unknown variable. Here, an is greater than zero because if it equals zero, the equation will cease to be quadratic and change to a linear equation, such as:
bx+c=0
As a result, we cannot refer to this equation as a quadratic equation.
Another name for the terms a, b, and c is quadratic coefficients.
The values of the unknown variable x that fulfil the quadratic equation are the solutions to the problem. These answers are referred to as roots
Given:
7-4x-x²
Find:
Write the quadratic equation 7-4x-x² in standard form
Solution:
f(x) = 7-4x-x²
Standard form of quadratic equation is
y= ax²+bx+c
So,
f(x) = -x²-4x+7
Therefore, 7-4x-x² in the standard form is -x²-4x+7
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