Math, asked by faiyyazansari4550, 10 months ago

write the quatratic quation 7-4x-x2 in the standard form​

Answers

Answered by tasmiyakhan421
2

Answer:

-x2-4x+7

Step-by-step explanation:

multiply whole eqn by - sign

x2+4x-7 is the standard form

Answered by arshikhan8123
0

Concept:

The definition of a quadratic equation as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. The quadratic equation has the following generic form:

ax² + bx + c = 0

where a, b, and c are numerical coefficients and x is an unknown variable. Here, an is greater than zero because if it equals zero, the equation will cease to be quadratic and change to a linear equation, such as:

bx+c=0

As a result, we cannot refer to this equation as a quadratic equation.

Another name for the terms a, b, and c is quadratic coefficients.

The values of the unknown variable x that fulfil the quadratic equation are the solutions to the problem. These answers are referred to as roots

Given:

7-4x-x²

Find:

Write the quadratic equation 7-4x-x² in standard form

Solution:

f(x) = 7-4x-x²

Standard form of quadratic equation is

y= ax²+bx+c

So,

f(x) = -x²-4x+7

Therefore, 7-4x-x² in the standard form​ is -x²-4x+7

#SPJ3

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