write the quotient and remainder y4+y3-y2+y-1 ÷ y3+1
Answers
Solution :-
Dividing y⁴ +y³ - y² + y - 1 by y³ + 1 we get
y³+1) y⁴ +y³ - y² + y - 1 (y + 1
y⁴ + y
y³ - y² - 1
y³ + 1
(-y² - 2)
therefore,
→ Remainder = (-y² - 2)
→ Quotient = (y + 1)
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Given : y⁴+y³-y²+y -1 ÷ y³+1
To Find : quotient and remainder
Solution:
y + 1
y³+1 _| y⁴+y³-y²+y -1 |_
y⁴ + y
__________
y³ -y² -1
y³ +1
___________
-y² - 2
Quotient = y + 1
Remainder = -y² - 2
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