Math, asked by parulmehta99, 9 months ago

Write the quotient when the sum of 2-digit number 49 and the number obtained by reversing the digits is divided by (i) 11 (ii) sum of digits

Answers

Answered by harishsathya2005
3

Answer:

(i) 12

(ii) 11

Step-by-step explanation:

Sum of numbers = 143

so, in 143/11

quotient = 12

remainder = 1

sum of digits = 13

so, in 143/13

quotient = 11

remainder = 0

Hope it helps

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