write the quotient when the sum of two digit number 79 and the number obtained by reversing the digit is divided by
a.) 11
b.)sum of digits
Answers
Answered by
2
Given units digit is x and tens digit is y
Hence the two digit number = 10y + x
Number obtained by reversing the digits = 10x + y
Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.
Hence (10y + x) + (10x + y) = 121
⇒ 11x + 11y = 121
∴ x + y = 11
Thus the required linear equation is x + y = 11.
Given units digit is x and tens digit is y
Hence the two digit number = 10y + x
Number obtained by reversing the digits = 10x + y
Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.
Hence (10y + x) + (10x + y) = 121
⇒ 11x + 11y = 121
∴ x + y = 11
Thus the required linear equation is x + y = 11.
Hence the two digit number = 10y + x
Number obtained by reversing the digits = 10x + y
Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.
Hence (10y + x) + (10x + y) = 121
⇒ 11x + 11y = 121
∴ x + y = 11
Thus the required linear equation is x + y = 11.
Given units digit is x and tens digit is y
Hence the two digit number = 10y + x
Number obtained by reversing the digits = 10x + y
Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.
Hence (10y + x) + (10x + y) = 121
⇒ 11x + 11y = 121
∴ x + y = 11
Thus the required linear equation is x + y = 11.
Similar questions