Question

write the ratio K.E and P.E of an electron

Answer 1

Answer:

Explanation:

According to Bohr's theory, the formula for calculating the Potential Energy of Hydrogen like species is −27.2(z2/n2)eV−27.2(z2/n2)eV

where z is the atomic number and n is the shell number.

For first shell of hydrogen atom put n=1 and z=1. You will get PE=−27.2eVPE=−27.2eV

PS PE is twice of KE (which has positive sign) in magnitude.

Since P.E. is twice of K.E. then its ratio will be = 1:2