Question

write the rationalising factor of denominator in ( 1/ under root 2 +under root 3 )

Answer 1

$\frac{1}{ \sqrt{2} + \sqrt{3} } \\ rationalisation \: factor = \sqrt{2} - \sqrt{3} \\ = \frac{1( \sqrt{2} - \sqrt{3}) }{( \sqrt{2} + \sqrt{3})( \sqrt{2} - \sqrt{3} ) } \\ = \frac{ \sqrt{2} - \sqrt{ 3} }{2 - 3} \\ = \frac{ \sqrt{2} - \sqrt{3} }{ - 1} \\ = \sqrt{3} - \sqrt{2} \: ans$