Question

write the rationalising factor of the denominator 1/√2+√3

Answer 1

Hey there! Here is your answer.

$\frac{1}{ \sqrt{2} + \sqrt{3} } \\ = \frac{1}{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{\sqrt{2} - \sqrt{3}} \\ \\ = \frac{\sqrt{2} - \sqrt{3}}{( { \sqrt{2} ) }^{2} - ( { \sqrt{3} )}^{2} } \\ = \frac{ \sqrt{2} - \sqrt{3} }{2 - 3 } \\ = \frac{ \sqrt{2} - \sqrt{3} }{ - 1}$

Hope this answer will help you!

⭐⭐⭐⭐

Plz mark as brainliest

⭐⭐⭐⭐

#Be Brainly✌️

⭐⭐⭐⭐

@Astudent

Answer 2

Answer:

hii mate

here is your answer

the rationalising factor of the denominator 1/√2+√3 is √2-√3

Hope it will help you

Mark it as brainliest plz