Question

Write the rationalising factor of the denominator in 1/√2+√3.

Answer 1

Hope it will be help you

Answer 2

Answer:

$Rationalising\: factor \:of\\\: the \: denominator \: in \: \frac{1}{\sqrt{2}+\sqrt{3}}\: \\is \: (\sqrt{2}-\sqrt{3})$

Step-by-step explanation:

$Rationalising\: factor \:of\\\: the \: denominator \: in \: \frac{1}{\sqrt{2}+\sqrt{3}}\\\: is \: (\sqrt{2}-\sqrt{3})$

$\frac{1}{(\sqrt{2}+\sqrt{3})}$

\* Multiply numerator and denominator by ,$(\sqrt{2}-\sqrt{3})$, we get*\

=$\frac{(\sqrt{2}-\sqrt{3})}{(\sqrt{2}+\sqrt{3})(\sqrt{2}-\sqrt{3})}$

=$\frac{(\sqrt{2}-\sqrt{3})}{(\sqrt{2})^{2}-(\sqrt{3})^{2})}$

=$\frac{(\sqrt{2}-\sqrt{3})}{2-3}$

=$\frac{(\sqrt{2}-\sqrt{3})}{-1}$

=$-(\sqrt{2}-\sqrt{3})$

[ Rational number ]

Therefore,

$Rationalising\: factor \:of\\\: the \: denominator \: in \: \frac{1}{\sqrt{2}+\sqrt{3}}\\\: is \: (\sqrt{2}-\sqrt{3})$

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