Question

write the rationalising factor of the denominator in ​

Answer 1

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1/√2+√3=√2-√3/-1

Answer 2

Hey Mate;

your answer is________________

step by step explaination:

given;

1/√2+√3-----------------(1)

the rationlising factor of 1/√2+√3 is (√2-√3) then multiply and divide the equation (1) with (√2-√3)

=1/√2-√3*√2-√3/√2-√3

=√2-√3/(√2+√3)(√2-√3)

=√2-√2/(√2²-√3²)

[it is in the form of (a+b)(a-b)=(a²-b²)]

=√2-√3/2-3

=√2-√3/-1

=- √2-√3-1

hope it helps you:)