Question

Write the rationalizing factor 6 by ^12-^3

Answer 1

heyy dear ☺☺


solution:->

answer is 2(√12-√3)3

Answer 2

$\frac{6}{ \sqrt{12}- \sqrt{13} } = \frac{6( \sqrt[]{12} + \sqrt{13} )}{\sqrt{12}- \sqrt{13} ( \sqrt[]{12} + \sqrt{13})} = \frac{6( \sqrt[]{12} + \sqrt{13})}{-1} = -6( \sqrt{12}+ \sqrt{13)}$