Question

write the reaction on cathode and anode during the electrolysis of water?

Answer 1

Answer:

The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g) At the positively charged anode, an oxidation reaction occurs, generating oxygen gas and giving electrons to the anode to complete the circuit: Oxidation at anode: 2 H2O(l) → O2(g) + 4 H+(aq) + 4e.

Explanation:

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Answer 2

At Cathode:

H+ + e -> H

H + H -> H2 (g)

At Anode:

OH- - e -> OH

4OH -> 2H2O + O2 (g)

Overall reaction:

2H -> 2H2 (g) + O2 (g)