Question

Write the reaction s of the final alkylation product of aniline with excess of methyl iodide in the presence of sodium carbonate

Answer 1

Answer:

Answer : On excessive alkylation with methyl iodide aniline gets converted into N,N,N-Trimethylanilinium iodide. After reacting it with sodium carbonate it get converted into N,N,N-Trimethylanilinium carbonate.

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