Question

Write the reaction to convert A. Propene to n propyl alcohol B. Propene to isopropyl alcohol

Answer 1

Answer: a. Propene to n-propyl alcohol

By the Hydroboration Oxidation Method:-

Ch₃-Ch=Ch₂ + 1. Bh₃/ 2. H₂O₂ , NaOH ⇒ Ch₃-Ch₂-Ch₂-OH

                                                                                                                                                   

b.  Propene to isopropyl alcohol

By Markonikov's Rule :-

Ch₃-Ch=Ch₂ + H-OH/H⁺ ⇒  Ch₃-Ch-Ch₃

                                                      |

                                                     OH

Answer 2

Answer:

A) n propyl alcohol can be prepared from propene by Hydroboration-oxidation process.

B) Isopropyl alcohol can be prepared from propene by the oxymercuration-reduction process.

Explanation:

A) Indirect Anti-Markovnikov's addition of water to alkene can be carried out by the hydroboration-oxidation process.

In this process, an alkene is treated with diborane and the product obtained is oxidised with alkaline hydrogen peroxide.

Propene, on undergoing hydroboration-oxidation process form n propyl alcohol.

The reaction is shown below.

CH₃-CH₂=CH₂ + B₂H₆ → CH₃-CH₂-CH₂BH₃

CH₃-CH₂-CH₂BH₃ + OH⁻/H₂O₂ → CH₃-CH₂-CH₂OH

The hydroboration-oxidation process is used to convert an alkene into primary alcohols.

B) Indirect Anti-Markovnikov's addition of water to alkene can also be carried out by the oxymercuration-reduction process.

Alkene in reaction with mercuric acetate forms an organometallic compound, which is then reduced by NaBH₄ to form alcohol.

The oxymercuration-reduction process can be used for obtaining isopropyl alcohol from propene.

The reaction is shown below.

CH₃-CH₂=CH₂ +  (CH₃COO)₂Hg → CH₃-CH(OH)-CH₂HgOOC.CH₃

CH₃-CH(OH)-CH₂HgOOC.CH₃ + NaBH₄  → CH₃-CH(OH)-CH₃