Question

write the reactions of formaldehyde and benzaldehyde in presence of 50% concentrated NaOh ​

Answer 1

Answer:

is a cross-canizzaro reaction.

is a cross-canizzaro reaction.You can see the mechanism in the attached picture.

is a cross-canizzaro reaction.You can see the mechanism in the attached picture.But in short you can solve it according to this-

is a cross-canizzaro reaction.You can see the mechanism in the attached picture.But in short you can solve it according to this-Make carboxylate ion of the carbonyl which is more reactive towards nucleophillic reaction and alcohol of that carbonyl which less reactive for the same.

is a cross-canizzaro reaction.You can see the mechanism in the attached picture.But in short you can solve it according to this-Make carboxylate ion of the carbonyl which is more reactive towards nucleophillic reaction and alcohol of that carbonyl which less reactive for the same.The hydride transfer step is the slowest step and hence the rate determining step.

Explanation:

thank you

Answer 2

Answer:

NaOH is uesd . benzaldehyde (C6H5CHO) + Formaldehyde (HCHO) ==》 Benzyl alcohol (C6H5CH2OH) + Formic acid (HCOOH).